From: "mame (Yusuke Endoh)" <noreply@...>
Date: 2021-12-06T14:04:57+00:00
Subject: [ruby-core:106515] [Ruby master Bug#18390] Enumerator::Lazy#find returns invalid value

Issue #18390 has been updated by mame (Yusuke Endoh).


I cannot reproduce the issue

```
$ ~/local/bin/ruby -ve 'p [1, 2, 3, 4].lazy.find(&:even?)'
ruby 3.0.2p107 (2021-07-07 revision 0db68f0233) [x86_64-linux]
2
```

Could you please elaborate what did you do? How did you install your ruby? What platform are you using? Is the script complete? How did you run the script?

----------------------------------------
Bug #18390: Enumerator::Lazy#find returns invalid value
https://bugs.ruby-lang.org/issues/18390#change-95176

* Author: cvss (Kirill Vechera)
* Status: Open
* Priority: Normal
* ruby -v: 3.0.2
* Backport: 2.6: UNKNOWN, 2.7: UNKNOWN, 3.0: UNKNOWN
----------------------------------------
There is a regression bug in `#find`
```ruby
# RUBY_VERSION 3.0.2
[1, 2, 3, 4].lazy.find(&:even?) # => nil (ERROR!), expected 2
[1, 2, 3, 4].find(&:even?).find(&:even?) # => 2
# RUBY_VERSION 2.4.1
[1, 2, 3, 4].lazy.find(&:even?) # => 2
[1, 2, 3, 4].find(&:even?) # => 2
```





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