From: "nobu (Nobuyoshi Nakada)" <noreply@...>
Date: 2021-10-07T15:26:28+00:00
Subject: [ruby-core:105591] [Ruby master Bug#18244] Unexpected errors output order

Issue #18244 has been updated by nobu (Nobuyoshi Nakada).


It sounds hard anyway regardless `stderr` buffering.
Why mixing `stdout` and `stderr`?

https://github.com/ruby/ruby/pull/4944

----------------------------------------
Bug #18244: Unexpected errors output order
https://bugs.ruby-lang.org/issues/18244#change-94060

* Author: inversion (Yura Babak)
* Status: Feedback
* Priority: Normal
* ruby -v: Ruby v3.0.2.107 (2021-07-07) [x64-mingw32]
* Backport: 2.6: UNKNOWN, 2.7: UNKNOWN, 3.0: UNKNOWN
----------------------------------------
Having this code:
```ruby
# $stderr.sync = false
warn 'warn'
$stderr.puts 'err'
fail
```
When I run it like this `ruby test.rb 2>err.log`, output is ok:
```
warn
err
test.rb:3:in `<main>': unhandled exception
```

But when I uncomment the first line ��� the output is different:
```
warn
test.rb:3:in `<main>': unhandled exception
err
```
Why buffered output to the `$stderr` redirected to file has the **wrong order**?
If we do not redirect to the file ��� the order is ok (exception is the last line of the output).

Checked platforms:
`Windows10: Ruby v3.0.2.107 (2021-07-07) [x64-mingw32]`
`Linux: Ruby 3.0.0p0 (2020-12-25 revision 95aff21468) [x86_64-linux]`



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