From: "austin (Austin Ziegler) via ruby-core" Date: 2024-11-09T02:54:03+00:00 Subject: [ruby-core:119858] [Ruby master Feature#20770] A *new* pipe operator proposal Issue #20770 has been updated by austin (Austin Ziegler). lpogic (��ukasz Pomiet��o) wrote in #note-39: > @austin, @AlexandreMagro I understand that this is a creature from the functional world. However, I wonder whether the current proposal (statement operator) would allow for such a forms: > ``` ruby > def foo > r |> (q_result = q(_)) |> p(_) > return q_result > end > # or > def foo > r |> q_result = q(_) |> p(_) > return q_result > end > > def bar > (r_result = r) |> q(_) |> p(_, r_result) > end > ``` My opposition to this concept in #note-37 stands for the same reasons. This is unreadable and has indeterminate scope. A pipeline operator is best used for passing the first parameter (like Elixir), the last parameter (some JavaScript `.pipe(���)` implementations; Go text templates), or an arbitrary parameter with an explicit marker (`it`, `_`, `_1`, etc.). Ruby already *has* pipeline-like method, `#then`. If `|>` or `.{}` acts as syntactic sugar for `#then`, I don't see an issue here. If, internally, it���s turned into the effective equivalent of `__pipe1 = r; __pipe2 = q(__pipe1); __pipe3 = p(__pipe2); __pipe3`, I don't see an issue here. But under no circumstances do I think that the effective temporary assignments should be exposed or made available to method calls further down the pipeline or after the pipeline is complete. That's too much magic. ---------------------------------------- Feature #20770: A *new* pipe operator proposal https://bugs.ruby-lang.org/issues/20770#change-110548 * Author: AlexandreMagro (Alexandre Magro) * Status: Open ---------------------------------------- Hello, This is my first contribution here. I have seen previous discussions around introducing a pipe operator, but it seems the community didn't reach a consensus. I would like to revisit this idea with a simpler approach, more of a syntactic sugar that aligns with how other languages implement the pipe operator, but without making significant changes to Ruby's syntax. Currently, we often write code like this: ```ruby value = half(square(add(value, 3))) ``` We can achieve the same result using the `then` method: ```ruby value = value.then { add(_1, 3) }.then { square(_1) }.then { half(_1) } ``` While `then` helps with readability, we can simplify it further using the proposed pipe operator: ```ruby value = add(value, 3) |> square(_1) |> half(_1) ``` Moreover, with the upcoming `it` feature in Ruby 3.4 (#18980), the code could look even cleaner: ```ruby value = add(value, 3) |> square(it) |> half(it) ``` This proposal uses the anonymous block argument `(_1)`, and with `it`, it simplifies the code without introducing complex syntax changes. It would allow us to achieve the same results as in other languages that support pipe operators, but in a way that feels natural to Ruby, using existing constructs like `then` underneath. I believe this operator would enhance code readability and maintainability, especially in cases where multiple operations are chained together. Thank you for considering this proposal! -- https://bugs.ruby-lang.org/ ______________________________________________ ruby-core mailing list -- ruby-core@ml.ruby-lang.org To unsubscribe send an email to ruby-core-leave@ml.ruby-lang.org ruby-core info -- https://ml.ruby-lang.org/mailman3/lists/ruby-core.ml.ruby-lang.org/