[ruby-core:119803] [Ruby master Bug#20790] Syntax acceptance of `*x = p rescue p 1` is different between parse.y and prism

Issue #20790 has been updated by mame (Yusuke Endoh).


Discussed at the dev meeting. Here is matz's preference.

```ruby
                    # current parse.y behavior   # matz's preference
*x = p rescue p 1   # (*x = p) rescue (p 1)      # *x = (p rescue (p 1))
*x = p 1 rescue p 1 # (*x = p 1) rescue (p 1)    # *x = ((p 1) rescue (p 1))
a, b = p rescue p   # a, b = (p rescue p)        # as is
x = p rescue p      # x = (p rescue p)           # as is
x = p rescue p 1    # x = (p rescue p) 1 (ERROR) # x = (p rescue p 1)
x = p 1 rescue p 1  # x = ((p 1) rescue (p 1))   # as is
```

@yui-knk @kddnewton What do you think?

----------------------------------------
Bug #20790: Syntax acceptance of `*x = p rescue p 1` is different between parse.y and prism
https://bugs.ruby-lang.org/issues/20790#change-110487

* Author: tompng (tomoya ishida)
* Status: Open
* ruby -v: ruby 3.4.0dev (2024-10-09T03:27:05Z master ed11a244dd) +PRISM [x86_64-linux]
* Backport: 3.1: UNKNOWN, 3.2: UNKNOWN, 3.3: UNKNOWN
----------------------------------------
~~~ruby
*x = p rescue p 1 # syntax error in prism
*x = p 1 rescue p 1 # both syntax ok
x = p rescue p 1 # both syntax error
x = p 1 rescue p 1 # both syntax ok
~~~
Which is correct? If `*x = p rescue p 1` is syntax valid, should `x = p rescue p 1` also be syntax valid?




-- 
https://bugs.ruby-lang.org/
 ______________________________________________
 ruby-core mailing list -- [e-mail]
 To unsubscribe send an email to [e-mail]
 ruby-core info -- https://ml.ruby-lang.org/mailman3/lists/ruby-core.ml.ruby-lang.org/