From: Jean-Hugues ROBERT <jean_hugues_robert@...>
Date: 2004-05-08T15:49:28+09:00
Subject: Re: use the ruby's stack for security

At 05:58 07/05/2004 +0900, you wrote:
>Hello,
>
>I need to play with the internal stack of the interpreter like this
>
>class A
>   def foo2
>     C.new.foo
>   end
>end
>
>class B
>   def foo2
>     C.new.foo
>   end
>end
>
>class C
>   def foo
>     klass=who_is_calling_me
>     if klass == A
>        puts 'GOOD'
>     elsif klass == B
>        puts 'BAD'
>     end
>   end
>end
>
>and now I want
>
>A.new.foo2
> >GOOD
>B.new.foo2
> >BAD
>
>the method who_is_calling_me must use the internal stack but how ??? here
>I use one level but in a real case there is a lot of levels
>I can't send this information via call to method
>
>I need this mechanisme to implement a security system.
>A logon session have all the informations for the security and all the
>objects called by the loggon session can use this informations to check
>security
>
>Anybody have an idea or it's impossible
>
>Thank you
>Bye

Hi,

There is caller(). But it returns a array of strings. A caller() that
would return an array of Binding objects is missing as of today.

A workaround that I can think of:

With caller()[0] you can get the name of the source file where the calling
method is defined, together with the exact line number.

Using this information it is probably possible to figure out what is
the class defined in that source file around that line number.

This is not an easy/clean path, but it is not an impossible one either.

Yours,

Jean-Hugues



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