From: "Mauricio Fernández" <batsman.geo@...>
Date: 2004-05-02T22:10:54+09:00
Subject: Re: Why no Proc##[]=() ? Why no Proc##replace() ?

On Sun, May 02, 2004 at 05:18:09PM +0900, Jean-Hugues ROBERT wrote:
> There are other ways to do this of course, without replace:
>   p = proc { @x ||= long_method }
> or (needed if result can be nil)
>   p = proc { @x = long_method unless defined? @x; @x }

It seems to me that you're assuming @x is an instance variable of the
Proc object, which it is not:

def foo; 1 end
#   =>nil
p = proc { @x ||= foo }
#   =>#<Proc:0x401f9cec@(irb):2>
@x
#   => (irb):3: warning: instance variable @x not initialized
#   =>nil
p[]
#   =>1
@x
#   =>1


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