From: Robert Klemme <bob.news@...>
Date: 2004-05-02T01:24:01+09:00
Subject: Re: Don't understand hashing...


"Michael Neumann" <mneumann@ntecs.de> schrieb im Newsbeitrag
news:20040501141807.GD794@miya.intranet.ntecs.de...
> Hi,
>
> Don't know why this happens:
>
>   class Lazy
>     self.methods.reject{|m| m =~ /^__(.*)__$/}.each {|m|
>       eval "def #{m}(*args, &block) __getobj__.send(:'#{m}', *args,
&block) end"
>     }
>
>     def initialize(&block)
>       @block = block
>     end
>
>     def __getobj__
>       if @block
>         @value = @block.call(*@args)
>         @block = nil
>       end
>       return @value
>     end
>
>     def method_missing(id, *args, &block)
>       __getobj__.send(id, *args, &block)
>     end
>
>     def hash
>       __getobj__.hash
>     end
>   end
>
>   id1 = Lazy.new {:Id}
>   id2 = :Id
>
>   p id1.hash == id2.hash # => true
>
>   h1 = {}
>   h2 = {}

Did you really mean to use two hashes?

    robert


>   h1[id1] = "id1"
>   h2[id2] = "id2"
>
>   p h1[id2] # => nil  (expect: "id1")
>   p h2[id1] # => "id2"
>
> I would have expected "id1" for h1[id2].
> Can someone enlighten me?
>
> Thanks.
>
>   Michael
>
>