From: ts <decoux@...>
Date: 2004-04-20T18:49:43+09:00
Subject: Re: convert yield to proc

>>>>> "Z" == Zsban Ambrus <ambrus@math.bme.hu> writes:

Z> 1. Only the first break causes a problem: 
 
 This is 1.9

svg% cat b.rb
#!./ruby
def x(&b)
   p "before"
   b.call
   p "after"
end

a = Proc.new { p "a"; break }
b = proc { p "b"; break }

x(&a)
x(&b)
svg%
 
svg% ruby -v b.rb
ruby 1.9.0 (2004-04-16) [i686-linux]
"before"
"a"
"before"
"b"
"after"
svg% 


Guy Decoux