From: Robert Klemme <bob.news@...>
Date: 2004-04-14T17:04:13+09:00
Subject: Re: New Ruby questions...


"Armin Roehrl" <armin@xss.de> schrieb im Newsbeitrag
news:407C6D08.2080509@xss.de...
>
> >
> >1. How can a regexp get the longer of two possibilities that are
> >ambiguous? For example, I need to be able to strip out register names:
> >
> >registers = '(r0|r1|r2|r3...|r10|r11|r12...)'
> >
> >In the regular expression, how can I get it to find r10 or r11 instead
of
> >stopping at r1?
> >
> register =~ /(r\d{2,})/

I guess he rather wants {1,2}

some_string.scan(/r\d{1,2}/) do |reg|
  puts "Found register: #{reg}"
end

You can even convert that to a number easily:

some_string.scan(/r(\d{1,2})/) do |match|
  no = match[0].to_i
  puts "Found register: #{no}"
end

Regards

    robert

> p $1 #-> r10
>
> \d is for a digit character
> {m,n} at least m and at most n repetitions of the preceding
>
> more info:
> http://dev.faeriemud.org/ruby-uguide/uguide05.html
> http://www.rubycentral.com/ref/ref_c_regexp.html
>
>