From: smejmoon@... (G'irts Kalnins)
Date: 2004-04-01T22:39:22+09:00
Subject: Re: How to get internal state of DateTime in seconds

> >How do you get internal state in seconds of DateTime instance? 
> >Or convert it to Time instance? 
> >
> >I want to compare two times with variable precision.
> >Below is my try to parse time from Common Log Format.
> >
> >require 'date'
> >str1 = '20/Nov/2003:08:08:09 +0200'
> >str2 = '20/Nov/2003:08:04:09 +0200'
> >fmt='%d/%b/%Y:%H:%M:%S %Z'
> >t1 = DateTime.strptime(str1, fmt)
> >t2 = DateTime.strptime(str2, fmt)
> >
> >#what is difference in minutes between these 2 times?

> Use to_i if you want it as an integer number of seconds
> 
> $ ruby -we 'puts Time.now.to_i'
> => 1080754316

There is no DateTime#to_i 
Right now I do like below and it looks ugly to me.

def dateToTime(str)
 d = DateTime.strptime(str, fmt='%d/%b/%Y:%H:%M:%S %Z')
 t = Time.local(d.year, d.month, d.day, d.hour, d.min, d.sec)
 t
end