From: Robert Klemme <bob.news@...>
Date: 2004-03-26T22:29:30+09:00
Subject: Re: [newbie] regexp - match quotation mark


"gabriele renzi" <surrender_it@remove.yahoo.it> schrieb im Newsbeitrag
news:lfb860lpiprtl3drl90n19ron1303i9n2p@4ax.com...
> il Fri, 26 Mar 2004 13:15:13 +0100, "Einar Buffer"
> <_ebuffer_@hotmail.com> ha scritto::
>
> >Hi, I'm trying to write a regular expression to match a quotation mark
> >inside a string. Actually, what I want is to extract the text between
two
> >quotation marks, like this:
> >
> >This should be "simple", but I can't do it.
> >
> >I want to extract the word simple with a regular expression.
> >
> >Thanks a lot!
>
> should fit:
> >> rgx=/"([^"]+)/
> => /"([^"]+)/
> >> m= rgx.match 'this is my "simple" sting'
> => #<MatchData:0x27c5760>
> >> m[1]
> => "simple"
>
> read like:
>  match a " and then read any charcater while it is not a "
>
> not that it does not handle escaped "

This might help.

    robert


module Scanner

RX=/
    "((?:[^"\\]|\\.)*)" | # double quoted strings
    '((?:[^'\\]|\\.)*)' | # single quoted strings
    (\S+)               # others
  /ox

def self.scan_non_ws(str, rx=RX)
  index = 0
  tokens = block_given? ? nil : []

  str.scan( rx ) do |m|
    token = m.detect{|x|not x.nil?}
    # puts "m=#{m.inspect}"
    # token = ( m[0]||m[1]||m[2] )
    # p token

    if tokens
      tokens << token
    else
      yield token, index
      index += 1
    end
  end

  tokens
end

end # module Scanner