From: Sam Roberts <sroberts@...>
Date: 2004-03-23T23:38:59+09:00
Subject: Re: How to pass a given block to a subroutine


Is this what you want?

/tmp % ruby -w y.rb
hello
world
/tmp % cat y.rb
def foo (*args, &ablock)
subroutine(*args, &ablock)
end

def subroutine *args
yield(*args)
end

foo("hello", "world") { |a,b| puts a; puts b; }

Cheers,
Sam

Wrote Lothar Scholz <mailinglists@scriptolutions.com>, on Tue, Mar 23, 2004 at 11:32:04PM +0900:
> Hello ,
> 
> I have a method 'foo' that takes a block, but the yield should
> be done in a subroutine.
> 
> ======================================================
> class Example
> 
>         def foo (*args)
>             subroutine *args
>         end
>         
>         def subroutine *arg
>             yield *arg # want to call the block given to foo
>         end
> 
> end
> 
> a = Example.new
> a.foo(10,20) { |a,b| print "#{a + b}\n" }
> =======================================================
> 
> If you ask why i want to do this:
> i have to replace an existing subroutine with my own version, that
> does something before yield is called. So i renamed the method
> and must now find a way to call it from my version.
> 
>  
> -- 
> Best regards,
>  Lothar                          mailto:mailinglists@scriptolutions.com
> 
> 

-- 
Sam Roberts <sroberts@certicom.com>