From: Eric Sunshine <sunshine@...>
Date: 2004-02-21T04:42:55+09:00
Subject: Re: [ruby] String#hex confusion

On Sat, 21 Feb 2004 04:31:07 +0900, Steven Jenkins wrote:
> x(main):008:0> '22'.sub(/(\d\d)/, "#{'\1'.hex.to_s}")
> => "0"
> I understand everything but the last line. What am I missing?

You are applying 'hex' to the literal string "\1".  Since '\' is not a hex  
digit, it returns 0.  What you really want is:

'22'.sub(/(\d\d)/) { "#{$1.hex.to_s}" }

-- ES