From: Charles Mills <boson@...>
Date: 2004-01-21T08:03:33+09:00
Subject: Re: question about blocks

On Wed, 21 Jan 2004, Simon Strandgaard wrote:

> On Wed, 21 Jan 2004 05:37:48 +0900, Ferenc Engard wrote:
> > How can I return a value from a block? "return" immediately returns from
> > the caller method, "break" bypasses the called method (which yielded the
> > block).
> > 
> > I have read something about this, but cannot remember where. I know the
> > syntax changed between 1.6.8 and 1.8.
> 
> How about this code?
>

I am using cygwin on XP and I get the following :
$ ./a.rb
before

> 
> server> ruby a.rb
> before
> after result=42
> server> expand -t2 a.rb 
> def test(&block)
>   puts "before"
>   res = nil
>   begin
>     res = block.call
>   rescue LocalJumpError => e
>     res = e.exit_value
>   end
>   puts "after result=#{res}"
> end
> 
> test { return 42 }
> server>
> 
> --
> Simon Strandgaard
> 
> 
here is the contents of my a.rb:
#!/usr/bin/ruby

def test(&block)
  puts "before"
  res = nil
  begin
    res = block.call
  rescue LocalJumpError => e
    res = e.exit_value
  end
  puts "after result=#{res}"
end

test { return 42 }

--
Charlie