From: elathan@...
Date: 2004-01-08T22:12:01+09:00
Subject: Re: convert a C/C++ array to a Ruby array

Quoting nobu.nokada@softhome.net: 
> > Actually it is part of the functionallity a C++ Class embeds:  
> >   
> > Foo::Foo(int n, double *f);  
> > double * Foo::Get();  
> >  
> > Okay, I can grab 'n' from the constructor and use it as the length  
> > of the Ruby/C array, but I wanted to make sure that there is no   
> > general way to procceed without messing with the details of the  
> > C/C++ code.  
>  
> If you can get the length from Foo, you can use it. 
 
Yes I know. The problem is that I am creating Ruby bindings for a large 
framework (more than 50 C++ classes) and the bindings code is automagically 
generated by reading the C++ prototypes, using a handmade Ruby  
parser/compiler. 
 
The generated code is quite readable and can be altered by a human, but 
I want to eliminate as much as I can the human intervation, so as the majority of the  
C++ prototypes to be compiled in the Ruby API without human editing. 
 
> What do you really intend, pseudo array? 
 
If I was doing this by myself, I would create a Ruby array of length Foo::n and  
populate it with the double(s) Foo::Get() returns.  
 
But this requires some magick, i.e. to understand further the functionality of Class Foo; 
not just read the prototypes and translate them using an application. So, I asked  
here if someone knows a better way... 
 
I checked SWIG and it returns a special SWIG object in that case... 
 
Regards, 
Elias