From: Robert Klemme <bob.news@...>
Date: 2003-12-04T02:32:04+09:00
Subject: Re: New to ruby--trouble with initializing arrays


"Josef 'Jupp' SCHUGT" <jupp@gmx.de> schrieb im Newsbeitrag
news:20031203004859.GC893@jupp%gmx.de...
> Hi!
>
> * Van Jacques; 2003-12-02, 23:31 UTC:
> > "Robert Klemme" <bob.news@gmx.net> wrote in message
news:<bqffva$22171v$1@ID-52924.news.uni-berlin.de>...
> [Object oriented life]
> > This is much more sophiscated than my program (with help from
> > another poster in a similar thread here in comp.lang.ruby), but I
> > used the
> >
> > row % size
> >
> > method for dealing with the edges also.
>
> The solution is not as sophisticated as it seems. Simply imagine that
> you number the fields like this (use fixed width font):
>
> <pre>
> : +--+--+--+--+--+--+
> : | 0| 1| 2| 3| 4| 5|
> : +--+--+--+--+--+--+
> : | 6| 7| 8| 9|10|11|
> : +--+--+--+--+--+--+
> : |12|13|14|15|16|17|
> : +--+--+--+--+--+--+
> : |18|19|20|21|22|23|
> : +--+--+--+--+--+--+
> : |24|25|26|27|28|29|
> : +--+--+--+--+--+--+
> : |30|31|32|33|34|35|
> : +--+--+--+--+--+--+
> </pre>
>
> If you now store them one after another going one to the right/left
> when assuming 0 and 5 are neighbors and current position is n results
> in (n +/- 1) modulo 6. For the row the same works - with the only
> difference that the result of the operation must be multiplied by the
> distance of the chunks representing a whole row (6 in this case).

I don't fully understand what you mean by "not as sophisticated as it
seems" since it does exactly what you describe. (Look into the pos()
method)

Now, did I or did you get something wrong? :-)

Kind regards

    robert