From: dblack@...
Date: 2003-10-09T20:24:37+09:00
Subject: Re: Enumerable#inject is surprising me...

Hi --

On Thu, 9 Oct 2003, ts wrote:

> >>>>> "d" == dblack  <dblack@superlink.net> writes:
>
> d>   $ ./ruby -e 'p ["a"].inject("start") {|x,y| break "b"}'
> d>   "start"
>
> d> I'm still not understanding why these should be different, or how
> d> "start" gets into the first one (the first block) at all.
>
> svg% ruby -e 'p ["x", "y"].inject("a") {|x,y| break 12 if y == "y"; x + y}'
> "ax"
> svg%
>
>  #inject ignore the value returned by break, and return the last result.

I thought "break val" executed a break *and* generated a return value
for the block at the same time:

  irb(main):011:0> a = proc { break 3 } .call; a
  => 3

Why wouldn't #inject treat the break the same way?


David

-- 
David Alan Black
home: dblack@superlink.net
work: blackdav@shu.edu
Web:  http://pirate.shu.edu/~blackdav