From: yvon.thoravallist@... (Yvon Thoraval)
Date: 2003-09-24T03:34:37+09:00
Subject: Re: [newbie] upper to lower first letter of a word

Mark J. Reed <markjreed@mail.com> wrote:

> Really?  That's arguably a bug.  What character encoding are you using?

I'm (more-or-less) sure about that because even if i put :
  l.gsub!(/\b[a-z������������������]+/) { |w| black_list.include?(w) ? w
: w.capitalize }

i get :
M�Con Sup�Rieur
when input was :
M�con sup�rieur

> Accented letters should be in \w, not \W, and therefore the
> space between one and an adjacent letter should not match \b.
> But Ruby regexes may be ASCII-only, and even if not, they're probably
> Latin-1-only.  So, for instance, they wouldn't work on UTF-8 strings.

precisely i'm using utf-8 �;)
however, i'm able to do a try using iso-8859-1, my word editor (Pepper
on MacOS X) is able to transcode within 2 clicks + one cut'n paste rom
utf to iso...
sounds strange to me because Ruby is coming from Japan where "special"
chars are every-day chars ???

[snip]

> The block has to compensate for that.  Something like this:
> 
>       string.gsub!(/(^|[- '])([a-z]+)/) { $1 + $2.capitalize }
> 
> Except that [a-z] won't match accented characters, so it's more like this:
> 
>       string.gsub!(/(^|[- '])([a-z����������������]+)/) { $1 + $2.capitalize }
> 
> And if the names aren't limited to French, then even more special characters
> creep in . . .

Yes, right, i know, for the time being, only about french and german
accentuated chars...

However because vintage are classified by area i might have to change
regex upon region...
-- 
Yvon