From: Thomas Sondergaard <thomas@...>
Date: 2003-09-22T10:28:14+09:00
Subject: Re: Making my own output stream

> This is probably a dumb question, but:
> if I want to make a class such that an instance of it
> can be assigned to $stdout without breaking anything,
> what does it need to implement?  Can I just define a #write
> method and include some mixin to handle the rest?

Unfortunately not. Implementing a new IO is not as trivial as it should be.
For rubyzip I have implemented an AbstractOutputStream module that
implements all the "output" methods of IO

  class TestOutputStream
        include AbstractOutputStream
        attr_accessor :buffer

        def initialize
            @buffer = ""
        end

        def << (data)
              @buffer << data
              self
        end
  end

You could try it and see if it works.

Cheers,

Thomas