From: "Kurt M. Dresner" <kdresner@...>
Date: 2003-09-14T11:31:47+09:00
Subject: Re: Ruby Object Model bothering me

Yeah, that's what I meant.  When I do a[i].push(foo) then all of a is
foo.  I forgot about the block for the constructor that gets run each
time.  Now I am a happy rubyist once again.

-Kurt

On Sun, Sep 14, 2003 at 09:25:37AM +0900, Robert Feldt wrote:
> Dan Doel <djd15@po.cwru.edu> skrev den Sun, 14 Sep 2003 09:11:16 +0900:
> 
> >Kurt M. Dresner wrote:
> >
> >>Ok, so I did
> >>
> >>a = Array.new(number, [])
> >>
> >>It's really bothering me that if I do a[i] = n, all of a is now n.
> >>
> >>Is there a graceful way to get around this?
> >>
> >>
> >
> >When I do:
> >
> >a = Array.new(6, [])
> >
> >a[5] = 3
> >
> >p a[2]
> >
> >I get [] printed out.
> >
> Yeah, but what about
> 
> a = Array.new(6, [])
> a[5] << 3
> p a[2]
> 
> ? ;)
> 
> I think the original poster might wanna try
> 
> a = Array.new(6) {Array.new}
> 
> but I'm not sure I understand what he wants...
> 
> Regards,
> 
> Robert
> 
> >- Dan
> >
> >
> >
> >
> 
> 
> 
> -- 
> Robert Feldt
> 
> 
>======= End of Original Message =======<