From: jzakiya@... (Jabari Zakiya)
Date: 2003-09-05T12:48:41+09:00
Subject: Re: Difference between .. and ... in boolean ranges

Oliver Dain <odain2@nospam.mindspring.com> wrote in message news:<usP5b.8858$tw6.6413@newsread4.news.pas.earthlink.net>...
> I'm a bit confused by some Ruby behavior I'm seeing with ranges.  As I 
> understand it the difference between
> 
> 0..5
> 
> and 
> 
> 0...5
> 
> is that the former includes the number 5 while the 2nd does not.  That 
> seems to be the case, but one would expect the same type of behavior 
> in boolean context.  For example, I'd think
> 
> 0.upto(9) do |x|
>   if (x==3)..(x==5)
>     puts "In the range: #{x}"
>   else
>     puts "Not in the range: #{x}"
>   end
> end
> 
> Would output:
> 
> Not in the range: 0
> Not in the range: 1
> Not in the range: 2
> In the range: 3
> In the range: 4
> In the range: 5
> Not in the range: 6
> Not in the range: 7
> Not in the range: 8
> Not in the range: 9
> 
> while using the 3 dot form like this:
> 
> 0.upto(9) do |x|
>   if (x==3)...(x==5)
>     puts "In the range: #{x}"
>   else
>     puts "Not in the range: #{x}"
>   end
> end
> 
> Would output:
> 
> Not in the range: 0
> Not in the range: 1
> Not in the range: 2
> In the range: 3
> In the range: 4
> Not in the range: 5
> Not in the range: 6
> Not in the range: 7
> Not in the range: 8
> Not in the range: 9
> 
> However, the 3 dot form doesn't work as expected.  It outputs the same 
> as the 2 dot form (which works as expected).  What gives?  This seems 
> unintuitive to me.  Any thoughts?
> 
> Thanks,
> Oliver
-----------------------------------------------------------------

change:  if (x==3)..(x==5)  and   (x==3)...(x==5)
to:      if (3..5).include?(x) or (3...5).include?(x)
or:      if (3..5).include? x  or (3...5).include? x

for second case, you get output: "Not in the range: 5"

Jabari Zakiya