From: Ben Giddings <bg-rubytalk@...>
Date: 2003-09-05T09:56:56+09:00
Subject: Re: Difference between .. and ... in boolean ranges

Sean O'Dell wrote:
> Try: if (3..5) === x

That'll probably work... but I'm curious to know if Oliver Dain's method 
  is supposed to work:

if (x==3)..(x==5)

and

if (x==3)...(x==5)

I'm surprised that they work at all, and I'm curious if the fact they 
work in some way is a fluke, or if it was a conscious decision to try to 
let them work like that.  I'd expect a syntax error, but then again, 
ranges as objects confuse me.  :)

Ben