From: Dan Doel <djd15@...>
Date: 2003-08-14T09:28:11+09:00
Subject: Re: Overloading ()


> Here's one construction that becomes possible because () is not an 
> operator:
>
>   def foo
>     3
>   end
>
>   foo = foo()
>   foo += 1
>   p foo    # ==> 4
>
> If () were an operator, the "foo()" syntax would have to be 
> interpreted as sending a #call message to the value of the local var 
> "foo".
>
> I don't know if that's the main justification or a side effect, though. 


Ah, that's true. I hadn't thought of that.

Seems like writing code like that is a bad idea, though, if you want to 
be able to understand it in the future. :)

- Dan