From: KONTRA Gergely <kgergely@...>
Date: 2003-08-07T23:17:13+09:00
Subject: Elegant solution for a loop-break problem

Hi!

I've tried to write a little program, which detect duplicate files.
My way to solve this is to have a hash for the known files like this
{ fileSize  => [[file1,file2],[file3,file4]],
  fileSize2 => [[file6,file7]] }

So, file1..file4 have the same size, file1 and file2's content is
identical, similarly file3 and file4 is identical.

First, the Hash is empty, and then I insert the files to be examined,
like this.

files = Hash.new { [] }
for filename in filesToBeAdded
  filesize=File.filesize(filename)
  for fn in filename[filesize]
    if equalContent(fn[0], filename)
      # add this file to this 'segment' TODO: alter files
      # next 'filename in filesToBeAdded'
    end
  end
  # if loop exited normally, create a new segment
end

So questions in general:
How can I alter items in a hash nicely?
Can I exit more loops with next/last/redo? (like in perl)
Is there something similar to python's for .. else ... structure? (Do
something, ONLY when the loop is terminated normally (without break)

thx
Gergo
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