From: ts <decoux@...>
Date: 2003-08-03T20:32:53+09:00
Subject: Re: 1.8.0-previewX  rb_sys_fail() on socket instead of an Exception.

>>>>> "K" == Kero van Gelder <kero@chello.single-dot.nl> writes:

K> If I break out of the first loop with the fix, everything works as
K> expected. But I can't help wondering why the second loop isn't scheduled,
K> when I give it "opportunity" to be scheduled. There's probably a good
K> reason, but I can't think of one.

 For me, it's scheduled, here an example

svg% ruby server.rb 
[...]
nil
nil
nil
nil
server.rb:19:in `write': Interrupt      from server.rb:19:in `puts'
        from server.rb:19
        from server.rb:18:in `loop'
        from server.rb:22
svg% 

 The program was stopped with Ctrl-C and it was interrupted in the second
 loop 


Guy Decoux