From: john_b_andrews@... (John Andrews)
Date: 2003-07-30T11:36:50+09:00
Subject: Re: -3 / 10 = -1  ?!

Thanks to Rudolf and Mark for answering my question.

I don't know what version of Perl you are both using, but
my Perl (5.6.1) on Linux *does* truncate to zero, agreeing
with C.

Here is the Perl program:

  use integer;

  $a = -3;
  $b = 100;
  $c = $a / $b;
  $d = $a % $b;

  print $c, "\n";
  print $d, "\n";

Here is the output:

  0
  -3

The same program in Ruby gives:

  -1
  97

Thanks,

JA

john_b_andrews@yahoo.com (John Andrews) wrote in message news:<b64fa1e8.0307281240.19d10f9f@posting.google.com>...
> Why does this program:
> 
>    print -3 / 10, "\n"
> 
> print -1?
> 
> If I underflow a negative int in C, I get zero.
> 
> If I underflow a negative integer in Perl (using "use integer"),
> I get zero.
> 
> Why does Ruby give me -1?
> 
> This behavior is not described (in any place I can find) in
> the pickaxe book.
> 
> Thanks,
> 
> JA