From: Kent Dahl <kentda@...>
Date: 2003-07-30T11:04:13+09:00
Subject: Re: How to rescue any exception in 1.8?

Philip Mak wrote:
> 
> This code will catch the exception in Ruby 1.6:
> 
> require 'timeout'
> begin
>         raise TimeoutError
> rescue
>         puts "Rescued!"
> end
> 
> But in Ruby 1.8, it will not catch the exception. I found out that if
> I do "rescue Exception" instead of just "rescue", it will work.
> 
> So, my question is, if I want to rescue any exception no matter what
> it is, do I have to start typing "rescue Exception" instead of
> "rescue"?

Yes.

Rescue without an Exception type only catches StandardError and
subclasses. The inheritance hierarchy of exceptions are one of the
changes between 1.6 and 1.8, IIRC...

[kentda@v052a kentda]$ ruby -v -e "require 'timeout';p
TimeoutError.ancestors"
ruby 1.6.8 (2002-12-24) [i386-linux-gnu]
[TimeoutError, StandardError, Exception, Object, Kernel]

[kentda@v052a kentda]$ /usr/local/bin/ruby -v -e "require 'timeout';p
TimeoutError.ancestors"
ruby 1.8.0 (2003-07-24) [i686-linux]
[Timeout::Error, Interrupt, SignalException, Exception, Object, Kernel]

HTH

-- 
(\[ Kent Dahl ]/)_    _~_    _____[ http://www.pvv.org/~kentda/ ]_____/~
 ))\_student_/((  \__d L b__/ (pre-) Master of Science in Technology  )
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