From: Daniel Carrera <dcarrera@...>
Date: 2003-07-24T08:39:59+09:00
Subject: Re: "regex literal in condition"

Funny thing is...
 -  When I begun writing the email the error was "parse error".
 -  While writing the email I noticed the "." and removed it.
 -  Then I got the error "regex literal in condition", so I 
    continued writing the email since I didn't know what this error
    meant.  But I forgot to update the code, so I left the dot.

On Thu, Jul 24, 2003 at 07:27:24AM +0900, Warren Brown wrote:
> Daniel,
> 
> > I'm getting an erorr that I don't understand.
> >
> > # My code
> > while gets.
> >     break if (/\<\!-{19} ending left_colum -{11}\>/)
> > end
> 
>     You've probably already figured this out, but the problem is the dot (.)
> after the call to gets in the first line.  I'm not too sure at first glance
> how ruby is parsing this, but any way you look at it, it's gonna' get it
> wrong.
> 
>     I hope this helps!
> 
>     - Warren Brown
> 
> 

-- 
Daniel Carrera    | OpenPGP fingerprint:
Mathematics Dept. | 6643 8C8B 3522 66CB D16C D779 2FDD 7DAC 9AF7 7A88
UMD, College Park | http://www.math.umd.edu/~dcarrera/pgp.html