From: Daniel Carrera Date: 2003-07-24T06:40:55+09:00 Subject: "regex literal in condition" -----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hello all, I'm getting an erorr that I don't understand. # My code while gets. break if (/\<\!-{19} ending left_colum -{11}\>/) end # Output: warning: regex literal in condition What is a "regex literal"? How is that different from any other regex? I just want to read a text file and skip all the lines until I arrive at the one matching the expression above. Can anyone see what I'm doing wrong? I really can't. Thanks. - -- Daniel Carrera | OpenPGP fingerprint: Mathematics Dept. | 6643 8C8B 3522 66CB D16C D779 2FDD 7DAC 9AF7 7A88 UMD, College Park | http://www.math.umd.edu/~dcarrera/pgp.html -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.2.2 (SunOS) iD8DBQE/HwDgnxE8DWHf+OcRAk2WAKDutetKGyuxPb13sA6l5cGE95Us/wCfUAAa ZaoQRjmY5pDZ6RGFegmh2YQ= =WHdb -----END PGP SIGNATURE-----