From: Brian Candler <B.Candler@...>
Date: 2003-07-15T04:58:31+09:00
Subject: Re: help - calling methods in a hash with parameters

On Tue, Jul 15, 2003 at 04:47:55AM +0900, John Platte wrote:
> eval myhash["bar"] + '("Thing to say")'

No, don't do that! Calling the compiler should be a last resort.

Instead, convert your method into an object reference so it can be put
straight into the hash:

myhash = {'foo' => method(:methodone), 'bar' => method(:methodtwo)}

myhash['foo'].call
myhash['bar'].call('hi, I am method two')

Check the docs for Method to find out other useful things (e.g. Method#arity
will tell you how many arguments it needs, before you call it)

Regards,

Brian.


> 
> On Monday, Jul 14, 2003, at 14:31 America/Chicago, Tuan Bui wrote:
> 
> >irb(main):001:0> def methodone
> >irb(main):002:1> puts "hi, i am method one"
> >irb(main):003:1> end
> >=> nil
> >irb(main):004:0> def methodtwo(input)
> >irb(main):005:1> puts input
> >irb(main):006:1> end
> >=> nil
> >irb(main):007:0> myhash = { 'foo' => 'methodone', 'bar' => 'methodtwo' 
> >}
> >=> {"foo"=>"methodone", "bar"=>"methodtwo"}
> >irb(main):008:0> eval myhash["foo"]
> >hi, i am method one
> >=> nil
> >irb(main):009:0> eval myhash["bar"] "hi, i am method two"
> >SyntaxError: compile error
> >(irb):9: parse error
> >	from (irb):9
> >irb(main):010:0>
> >
> >
> >In other words, how do I pass a parameter to method two?
> 
> -- 
> John Platte
> Principal Consultant, NIKA Consulting
> http://nikaconsulting.com/
> 
>