From: "Mauricio Fernández" <batsman.geo@...>
Date: 2003-07-09T18:37:09+09:00
Subject: Re: Possible use for a continuation? [Generating all factors of a given number]

On Wed, Jul 09, 2003 at 05:40:40PM +0900, Harry Ohlsen wrote:
> Anyway, I have something that works.  But, I'd still be interested if 
> someone feels like showing me how to achieve the equivalent generator 
> that's being used in the last code snippet.

http://www.rubygarden.org/ruby?RubyFromPython

Scroll down to 'Generators'.


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batsman dot geo at yahoo dot com

No, that's wrong too.  Now there's a race condition between the rm and
the mv.  Hmm, I need more coffee.
	-- Guy Maor on Debian Bug#25228