From: ts Date: 2000-12-17T03:27:45+09:00 Subject: [ruby-talk:7452] Re: question: 'A'..'k' >>>>> "M" == Mathieu Bouchard writes: M> k=0; ("A".."k").each{|x|k+=1}; k M> I expected 11, I got 26. Why is that? why 11 ? You have 11 with ("A".."K") Guy Decoux