From: daz <dooby@...10.karoo.co.uk>
Date: 2003-06-22T12:26:26+09:00
Subject: Re: I worked it out (was Re: 2 dimentional array in ruby)


"Jacek Podkanski" wrote:

> This is my way of doing it. It's different from other's suggestions, but it
> suits my needs. I anyody comes up with shorter solution please let me know.
>
> #! /usr/bin/ruby
>
> #table acces function
> def ta(table,row,column,value)
>   r=table[row];  r[column]=value
> end
>
> #### create 2 dimensional array #############
> t=Array.new
> for x in 0..9
>   row=Array.new
>   for y in 0..9
>     row[y]=(x+1)*(y+1)
>   end#for
>   t<<row
> end#for
> #######################################
> puts t.inspect
>
>
> --
> Jacek Podkanski

Hi Jacek,

map (same as collect) returns an array, so you can
create an array of 10 arrays, each having 10 elements
like this ...


### Create multiplication table
Mult = (1..10).map{|x| (1..10).map{|y| x * y }}

### Table access function
def ta(row, column)
  Mult[row-1][column-1]
end

### Test it
p ta(1, 1)     #=> 1
p ta(7, 6)     #=> 42
p ta(6, 7)     #=> 42
p ta(10, 10)   #=> 100

### Display table
Mult.each{|r| r.each{|c| printf("%4d", c)}; puts}


daz