From: Chris Pine Date: 2003-06-13T21:01:59+09:00 Subject: Re: Reason for implicit block syntax ? ----- Original Message ----- From: "Mauricio Fern�ndez" My bet is that he means my_func bar, baz { ... block ... } as opposed to block = proc { ... block .., } ---------------------------- But since `proc' is just a method which takes a block... aren't these practically identical syntax? As I see it, there's really only one way to make a block. Chris