From: ts Date: 2003-06-05T01:50:25+09:00 Subject: Re: ruby-dev summary 20201 - 20315 >>>>> "P" == Paul Brannan writes: P> What exactly does this mean? Do both forms of '*' now use the same P> method for conversion to array? If so, which one? svg% cat b.rb #!/usr/bin/ruby class A def to_a [1, 2] end end def a(*args) p args end a(*A.new) svg% svg% ruby b.rb [1, 2] svg% Guy Decoux