From: "meinrad.recheis" <my.name.here@...>
Date: 2003-05-12T06:56:27+09:00
Subject: efficiency advice needed

hi,

i got to interleave the alpha channel with an rgb image both given as raw 
files: please don't laugh at me, but i found myself writing this very short 
but slow code:

rgb = File.new rgbfile, 'rb'
# this raw file contains rgb bytes in interleaved order, so one pixel is 3 
bytes

alpha = File.new alphafile, 'rb'
# contains 1 byte/pixel alpha channel

#desired result: a binary string, rgba interleaved, 4 byte/pixel, = 
4*width*height bytes

data = ''
(width*height).times{
  data += rgb.read( 3) + alpha.read( 1)
}

i think alternately reading some bytes is slowing down alot. but also loops 
operating on strings are
slow, i think. i know some solutions, but i don t know which one to use.
are there any suggestions how to do this most efficiently in ruby?

-- thanks, mr