From: "Morris, Chris" Date: 2000-12-13T04:53:33+09:00 Subject: [ruby-talk:7104] Re: Rubyize this method > Not quite the same, though. Chris' method > > lopOff("fred", "e") would return "d" > "fred".lopOff("e") would return "frd" The first one is the one I'm going for, although the way I'm using it, either implementation would do the job. Let's say I want to stick with the first way ... any suggestions there? Oh, wait ... Guy's: s[/^#{substr}/] = "" ... looks like it would work. (Although reg expressions read like German to me ). The way I use it, I always have the substr at the front of the str. Thanks to all. Chris