From: Jim Freeze <jim@...>
Date: 2003-04-14T23:56:45+09:00
Subject: Re: How do I call a regex from C?

On Monday, 14 April 2003 at 23:25:03 +0900, ts wrote:
> >>>>> "J" == Jim Freeze <jim@freeze.org> writes:
> 
> J> If I use rb_funcall, Do I have to make two calls? One
> J> to create the regex and one to apply it? 
> J> Is there a faster way?
> 
>  It really depend what call you want to do.
> 
>  For example, String#sub can take a String or a Regexp as the first
>  argument. You can call Regexp::new (via rb_funcall)
> 
>  To create a regexp you have also rb_reg_regcomp(VALUE). You can use
>  perhaps also rb_reg_match()  
> 
> 
> Guy Decoux

Ok, this is what I have done so far:

static VALUE re_equal;

in_some_init_func() {
  re_equal = rb_reg_regcomp("\\s*=\\s");
  re_space = rb_reg_regcomp("\\s+");
}

in_main_loop() {
 VALUE sp = rb_str_new2(" ");

 // I don't think this is allowed -------v
 rb_funcall(line, "gsub!", 2, re_equal, "=") 

 // should probably be this.
 rb_funcall(line, "gsub!", 2, re_equal, sp) 
}

If I just want to replace with a character, is there
a faster way than to create a string object?

What if I want to replace with an empty string ""?

Thanks

-- 
Jim Freeze
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