From: dblack@...
Date: 2003-04-01T12:24:07+09:00
Subject: Re: Change to /.../.match("foo") behaviour in 1.6.8?

Hi --

On Tue, 1 Apr 2003, Yukihiro Matsumoto wrote:

> Hi,
>
> In message "Change to /.../.match("foo") behaviour in 1.6.8?"
>     on 03/03/31, Austin Ziegler <austin@halostatue.ca> writes:
>
> |In 1.6.7 and 1.7, I had the following line work:
> |
> |      l, m1, m2 = /((?:\S+\s+){11})(.+)/.match(line)
> |
> |This meant that #match return worked like an array.
>
> Put "*" before the expression, e.g.
>
> 	l, m1, m2 = */((?:\S+\s+){11})(.+)/.match(line)

I'm getting confused....  It looks like 1.8 goes back to the 1.4
behavior -- am I right about that?

  candle:~$ ruby -ve 'a, b = /(.)/.match("ab"); p a,b'
  ruby 1.8.0 (2003-03-03) [i686-linux]
  "a"
  "a"

and for the other behavior, the * doesn't seem to change it (in this
1.6.8 example):

  candle:~$ ruby/1.6.8/bin/ruby -ve 'a, b = */(.)/.match("ab"); p a,b'
  ruby 1.6.8 (2002-12-24) [i686-linux]
  #<MatchData:0x401bb98c>
  nil


David

-- 
David Alan Black
home: dblack@superlink.net
work: blackdav@shu.edu
Web:  http://pirate.shu.edu/~blackdav