From: Bulat Ziganshin <bulatz@...>
Date: 2003-03-18T14:18:20+09:00
Subject: Re: Accessing hash values sorted by their keys

Hello Josef,

Tuesday, March 18, 2003, 2:49:45 AM, you wrote:

JJS> Is an elegant way of doing this?

JJS> h.keys.sort.each { |key|
JJS>   puts h[key]
JJS> }

puts h[h.keys.sort]

JJS> works but seems unneccarily complicated.

JJS> Is there some analogy to the following Fortran 90 snipplet?

JJS> DIMENSION a (30, 40), i (5)
JJS> PARAMETER (i = (/5, 10, 15, 20, 25 /) )

JJS> x1 = a(1, :)
JJS> x2 = a(10, 2:40:2)
JJS> x3 = a(1:10, 2:40:2)
JJS> x4 = f(2, i)

JJS> ! x1 through x4 are arrays
JJS> ! x1 is 1st row of a
JJS> ! x2 is every 2nd element of the 10th row starting with 2nd element
JJS> ! x3 is every 2nd element of rows 1 through 10 "    "    "     "
JJS> ! x4 is elements 5, 10, 15, 20, 25 of 2nd row

JJS> 'h.sort[*][1].each' would be great...

you also can use Range for subscripring array. For a real work
with multidimensional arrays it is better to use specific extension,
NumericalArray? (i don't remember)

-- 
Best regards,
 Bulat                            mailto:bulatz@integ.ru