From: Josef 'Jupp' Schugt <jupp@...>
Date: 2003-03-18T08:49:45+09:00
Subject: Accessing hash values sorted by their keys

Is an elegant way of doing this?

h.keys.sort.each { |key|
  puts h[key]
}

works but seems unneccarily complicated.

Is there some analogy to the following Fortran 90 snipplet?

DIMENSION a (30, 40), i (5)
PARAMETER (i = (/5, 10, 15, 20, 25 /) )

x1 = a(1, :)
x2 = a(10, 2:40:2)
x3 = a(1:10, 2:40:2)
x4 = f(2, i)

! x1 through x4 are arrays
! x1 is 1st row of a
! x2 is every 2nd element of the 10th row starting with 2nd element
! x3 is every 2nd element of rows 1 through 10 "    "    "     "
! x4 is elements 5, 10, 15, 20, 25 of 2nd row

'h.sort[*][1].each' would be great...

Josef 'Jupp' Schugt
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