From: Tanaka Akira <akr@...17n.org>
Date: 2003-02-11T13:54:11+09:00
Subject: Re: Operator reordering, good idea? (was Re: ruby-dev summary 19457-19539)

In article <20030211044054.GA15912@debian>,
  Sam Roberts <sroberts@uniserve.com> writes:

> I don't understand, doesn't
>
> (a + b) == (b + a)
>
> in general?

For example, "a" + "b" != "b" + "a".

> Actually, I think in general neither should be commutative, they aren't
> math, they are method calls.

method call is just a implementation.

Do you have any example for == which should not be commutative?
-- 
Tanaka Akira