From: ahoward <ahoward@...>
Date: 2003-02-04T06:15:01+09:00
Subject: Re: ruby-dev summary 19437-19455

On Tue, 4 Feb 2003, Yukihiro Matsumoto wrote:

> Hi,
>
> In message "Re: ruby-dev summary 19437-19455"
>     on 03/02/04, ahoward <ahoward@fsl.noaa.gov> writes:
>
> |> C's static is global that extent is limited to enclosing block (or file).
> |> I don't think it's what we want.
>
> |      static int count = 0;				      // <-- THIS STATIC
>
> I know.  It's still global with constant initializer.

i'm not exactly sure how?  my understanding is from the K&R book.  if what you
are saying is true, i'm not sure exactly how this works :

~/eg/c > cat static.c

  #include <stdlib.h>
  #include <stdio.h>

  void
  foo (void)
  {
    static int count = 0;
    printf ("%s called %d times\n", __FUNCTION__, count++);
  }

  void
  bar (void)
  {
    static int count = 0;
    printf ("%s called %d times\n", __FUNCTION__, count++);
  }

~/eg/c > cat main.c

  extern void foo (void);
  extern void bar (void);

  int
  main (argc, argv, env)
       int argc;
       char **argv;
       char **env;
  {
    int i;

    for (i = 0; i < 4; i++)
      {
	foo ();
	bar ();
      }
    return 0;
  }

~/eg/c > gcc main.c static.c && a.out

  foo called 0 times
  bar called 0 times
  foo called 1 times
  bar called 1 times
  foo called 2 times
  bar called 2 times
  foo called 3 times
  bar called 3 times

this _looks_ like the two counts are made 'private' to foo and bar, and also
that the scope is not global, although i realize that allocation in the data
segment might be what you meant by 'global'.  i was referring to their scopes,
which certainly seem not to be global.  i have a feeling you will insert a
reason that i am wrong,

  here -> <reason></reason>

in any case, a ruby 'static' could be similar in meaning if not in
implimentation.  perhaps this is more difficult than i realize to impl.

in any case it seems like it would be usefull to have this _ability_ if not
the syntax (no one ever likes my syntax ideas ;-) ).

-a


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