From: dblack@...
Date: 2003-01-14T02:13:20+09:00
Subject: Re: sorting with the Swartzian transform

Hi --

On Tue, 14 Jan 2003, Daniel Carrera wrote:

> On Mon, 13 Jan 2003, Bulat Ziganshin wrote:
>
> > Hello Martin,
> >
> > Sunday, January 12, 2003, 11:48:27 AM, you wrote:
> >
> > MD> class Array
> > MD>   def ssort(&block)
> > MD>     map {{|i| [&block.call(i), i]}\
> > MD>     .sort {|a,b| a[0] <=> b[0]}\
> >
> > just ".sort" will be faster (in most cases :)
>
> Yes, but it does something different.  '.sort' sorts in ASCIIbetical
> order (so 10 comes before 2) , whereas <=> is a numerical sort.

"10" (string) comes before "2", but 2 comes before 10:

  irb(main):008:0> [10,2].sort
  => [2, 10]
  irb(main):009:0> ["10","2"].sort
  => ["10", "2"]

(both based on <=>)


David

-- 
David Alan Black
home: dblack@candle.superlink.net
work: blackdav@shu.edu
Web:  http://pirate.shu.edu/~blackdav