From: Radek Hnilica <Radek@...>
Date: 2002-12-19T18:33:56+09:00
Subject: Re: Few question about IO

On Thu, Dec 19, 2002 at 05:41:46PM +0900, Greg Millam wrote:
> On Thu, 19 Dec 2002, Radek Hnilica wrote:
> 
> \s is all white space characters, and \S is all non-whitespace characters.
> since you also wish to match end of line, this might work:
> 
> s.gsub(%r[(\s|^)#{word}(\s|$)],%Q[\1#{id}\2])
> 
> This has one flaw:
> 
> s = "foo foo foo foo"
> word = "foo"
> id = "bar"
> 
> s.gsub(%r[(\s|^)#{word}(\s|$)],%Q[\1#{id}\2])
> gets: bar foo bar foo
> because the space after the first foo (bar) is ignored when looking for
> the first space of the next word.

does not work for me:
irb(main):032:0> ": dbl dup + ;".gsub(%r[(\s|^)\+(\s|$)], %Q[\1:plus:\2])
=> ": dbl dup\001:plus:\002;"

something is wrong with \1 and \2

$ ruby --version
ruby 1.7.3 (2002-12-17) [i586-linux]


-- 
Radek Hnilica <Radek at Hnilica dot CZ>
=======================================
No matter how far down the wrong road you've gone, turn back.
						Turkish proverb