From: Shannon Fang <xrfang@...>
Date: 2002-12-03T18:19:27+09:00
Subject: Re: call-by-reference problem again

I think it is explained already in the discussion. I am clear now, but I 
still think it is different. Because if you do this:

a=b=c=d=e="hello"
a="world"

Then, b,  c, d, e, won't be changed.

Shannon



>From: Mauricio Fern�ndez <batsman.geo@yahoo.com>
>Reply-To: ruby-talk@ruby-lang.org
>To: ruby-talk@ruby-lang.org (ruby-talk ML)
>Subject: Re: call-by-reference problem again
>Date: Tue, 3 Dec 2002 17:31:00 +0900
>
>On Tue, Dec 03, 2002 at 08:18:39AM +0900, Shannon Fang wrote:
> > Hi,
> >
> > I modified my code, I'm afraid that I can't find it. It is like the
> > following:
> >
> > class MailInfo
> >   def initialize
> >     @path=@recipients=@from=Array.new
> >     ...
> >   end
> >   def parse
> >          case header
> > 	when "TO", "CC", "BCC"
> > 		@recipients << header
> > 	when "RECEIVED"
> > 		@path << header
> >          end
> >   end
> >   ...
> > end
> >
> > in the above code, the arrays will interfere with each other. The way to
> > solve it is not to use chained assignment.
>
>Yes, because they are all the same array :)
>But why is it any different from String(s)?
>
>--
>  _           _
>| |__   __ _| |_ ___ _ __ ___   __ _ _ __
>| '_ \ / _` | __/ __| '_ ` _ \ / _` | '_ \
>| |_) | (_| | |_\__ \ | | | | | (_| | | | |
>|_.__/ \__,_|\__|___/_| |_| |_|\__,_|_| |_|
>	Running Debian GNU/Linux Sid (unstable)
>batsman dot geo at yahoo dot com
>
>Linux - Das System fuer schlaue Maedchen ;)
>	-- banshee


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