From: dblack@...
Date: 2002-11-19T00:25:56+09:00
Subject: Re: ruby-dev summary 18711-18810

Hi --

On Mon, 18 Nov 2002, Minero Aoki wrote:

>     # Enumerable#zip
>     for x,y in a.zip(b) do ... end
>     a.zip(b).each {|x,y| ...}
>         # Problem: If the length of a and b are different,
>         # which one should we choose?  The default value/block does
>         # not resolve this problem, because it is equal to the
>         # "choose longest" strategy.

Since a is the receiver, it would seem natural to me to have the
zip'ping only go the length of a.

Also -- separate point, but maybe related -- do we need "each"?
What about:

  a.zip(b) {|x,y| ... }

i.e., have zip itself iterate (rather than have to iterate through
the returned array).


David

-- 
David Alan Black
home: dblack@candle.superlink.net
work: blackdav@shu.edu
Web:  http://pirate.shu.edu/~blackdav