From: Michael Campbell <michael_s_campbell@...>
Date: 2002-11-16T06:19:16+09:00
Subject: Re: Regexp: What does //o do?

> Yes. It's not completely clear to me when it will be recompiled
> and when it won't be. Above it is not. Below it is.
> 
> irb(main):001:0> s="a"
> "a"
> irb(main):002:0> /#{s}/o
> /a/
> irb(main):003:0> s="b"
> "b"
> irb(main):004:0> /#{s}/o
> /b/

This is 2 different regex's, even though they evaluate to the same,
so each one is compiled once.  (2 different spots in the source code)

> 
> irb(main):016:0> def foo(s)
> irb(main):017:1> re = /#{s}/o
> irb(main):018:1> p re
> irb(main):019:1> re = nil
> irb(main):020:1> end
> nil
> irb(main):021:0> foo("a")
> /a/
> nil
> irb(main):022:0> foo("b")
> /a/
> nil
> 
> and I'm confused even more.

That's the SAME regex (same spot in the source code) used twice. 
Your first example was 2 different regex's, used once each.




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