From: Paul Brannan Date: 2002-11-08T06:27:07+09:00 Subject: Re: v.polar = rho, theta On Fri, Nov 08, 2002 at 06:09:17AM +0900, Hans Fugal wrote: > But it struck me that defining polar=(rho,theta) would be more > ruby-like, and I expected to call it like so: v.polar = 1, 3.14 > That doesn't work, though. Is there a reason why Ruby doesn't treat this case like like it treats multiple assignment to a variable? Paul