From: William Djaja Tjokroaminata <billtj@...>
Date: 2002-10-10T23:54:59+09:00
Subject: Re: superclass method calling problem

Hi Peter,

My "not-so-elegant" solution is to provide an extra parameter in B#foo:

# ----------------------------------------
# my baseclass
class A
    def initialize(b)
        puts "Initialized A: #{b}"
    end

    # need to call this from B
    def foo(a)
        puts "Foo A: #{a}"
    end
end

# my derived class
class B < A
    def initialize(c)
        super(c)
        foo (c, true)      # need an extra parameter here
        puts "Initialized B: #{c}"
    end

    # need an extra parameter here
    def foo(d, par = false)
        if par
            super (d)
        else
            puts "Foo B: #{d}"
        end
    end
end

x = B.new(10)
x.foo (20)
# ----------------------------------------

Probably other people can provide a better solution.

I guess you miss the C++ scoping operator ::?  :)

Regards,

Bill
===========================================================================
Peter Schueller <peter.schueller@solution-x.com> wrote:
> I want that if i call B.new(10) that B is initialized and calls the old
> function foo from class A (from its ancestor).
> but i have to overload the foo function so simply calling foo(c) would not
> work.

> The Output should be:
>> x = B.new(10)
> Initialized A: 10
> Foo A: 10
> Initialized B: 10

>> x.foo(20)
> Foo B: 20